(4x-1)(x+3)-(2x-1)^2=26

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Solution for (4x-1)(x+3)-(2x-1)^2=26 equation: 



(4x-1)(x+3)-(2x-1)^2=26

We move all terms to the left:

(4x-1)(x+3)-(2x-1)^2-(26)=0

We multiply parentheses ..

(+4x^2+12x-1x-3)-(2x-1)^2-26=0

We get rid of parentheses

4x^2+12x-1x-(2x-1)^2-3-26=0

We add all the numbers together, and all the variables

4x^2+11x-(2x-1)^2-29=0

We move all terms containing x to the left, all other terms to the right

4x^2+11x-(2x-1)^2=29

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